Chapter Name: Chemical Reactions and Equations
Activity Name: Double displacement reaction in Chemical Reactions and Equations
In this experiment, a double displacement reaction is performed between lead nitrate (Pb(NO3)2) and potassium iodide (KI) solutions.
When these two solutions are mixed, a yellow-colored precipitate, lead iodide (PbI2), is formed, which is insoluble in water. This reaction demonstrates the characteristics of a double displacement reaction, where the reactants exchange their constituents and form two products.
- Lead nitrate (Pb(NO3)2)
- Potassium iodide (KI)
- Distilled water
- Test tubes
Step by Step Procedure:
- Take a pinch of lead nitrate (Pb(NO3)2) and dissolve it in 5.0ml of distilled water in a test tube.
- Take a pinch of potassium iodide (KI) in a separate test tube and dissolve it in distilled water.
- Mix the lead nitrate solution with the potassium iodide solution.
- Observe the reaction mixture.
- A yellow-colored substance that is insoluble in water is formed as a precipitate. This precipitate is identified as lead iodide (PbI2).
- Handle the chemicals with care, and avoid direct contact with the skin or eyes.
- Perform the experiment in a well-ventilated area or a fume hood to avoid inhaling any fumes or vapors.
- Use clean and dry test tubes to ensure accurate observations.
- Dispose of the chemicals and the precipitate properly according to the guidelines for chemical waste disposal.
Lesson Learnt from Experiment:
This experiment demonstrates a double displacement reaction, where the lead nitrate and potassium iodide solutions react to form lead iodide as a precipitate. Double displacement reactions involve the exchange of ions between two reactants, resulting in the formation of two products.